Optimal. Leaf size=349 \[ \frac{8 i x \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (2,-e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{8 i x \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (2,e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{16 i \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (3,-e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{16 i \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (3,e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{4 i x^2 \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \tanh ^{-1}\left (e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f \sqrt{a+i a \sinh (e+f x)}} \]
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Rubi [A] time = 0.2019, antiderivative size = 349, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {3319, 4182, 2531, 2282, 6589} \[ \frac{8 i x \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (2,-e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{8 i x \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (2,e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{16 i \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (3,-e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{16 i \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \text{PolyLog}\left (3,e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{4 i x^2 \cosh \left (\frac{e}{2}+\frac{f x}{2}+\frac{i \pi }{4}\right ) \tanh ^{-1}\left (e^{\frac{f x}{2}+\frac{1}{4} (2 e-i \pi )}\right )}{f \sqrt{a+i a \sinh (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 3319
Rule 4182
Rule 2531
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{x^2}{\sqrt{a+i a \sinh (e+f x)}} \, dx &=\frac{\sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \int x^2 \text{csch}\left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right ) \, dx}{\sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{4 i x^2 \tanh ^{-1}\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f \sqrt{a+i a \sinh (e+f x)}}-\frac{\left (4 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \int x \log \left (1-e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right ) \, dx}{f \sqrt{a+i a \sinh (e+f x)}}+\frac{\left (4 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \int x \log \left (1+e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right ) \, dx}{f \sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{4 i x^2 \tanh ^{-1}\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f \sqrt{a+i a \sinh (e+f x)}}+\frac{8 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (-e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{8 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}+\frac{\left (8 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \int \text{Li}_2\left (-e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right ) \, dx}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{\left (8 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \int \text{Li}_2\left (e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right ) \, dx}{f^2 \sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{4 i x^2 \tanh ^{-1}\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f \sqrt{a+i a \sinh (e+f x)}}+\frac{8 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (-e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{8 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}+\frac{\left (16 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}}-\frac{\left (16 \sinh \left (\frac{e}{2}-\frac{i \pi }{4}+\frac{f x}{2}\right )\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,e^{-i \left (\frac{i e}{2}+\frac{\pi }{4}\right )+\frac{f x}{2}}\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}}\\ &=\frac{4 i x^2 \tanh ^{-1}\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right ) \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right )}{f \sqrt{a+i a \sinh (e+f x)}}+\frac{8 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (-e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{8 i x \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_2\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{f^2 \sqrt{a+i a \sinh (e+f x)}}-\frac{16 i \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_3\left (-e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}}+\frac{16 i \cosh \left (\frac{e}{2}+\frac{i \pi }{4}+\frac{f x}{2}\right ) \text{Li}_3\left (e^{\frac{1}{4} (2 e-i \pi )+\frac{f x}{2}}\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}}\\ \end{align*}
Mathematica [A] time = 0.973604, size = 276, normalized size = 0.79 \[ \frac{(1+i) (-1)^{3/4} \left (\sinh \left (\frac{1}{2} (e+f x)\right )-i \cosh \left (\frac{1}{2} (e+f x)\right )\right ) \left (-4 f x \text{PolyLog}\left (2,-(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )+4 f x \text{PolyLog}\left (2,(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )+8 \text{PolyLog}\left (3,-(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )-8 \text{PolyLog}\left (3,(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )-e^2 \log \left (1-(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )+e^2 \log \left ((-1)^{3/4} e^{\frac{1}{2} (e+f x)}+1\right )-2 i e^2 \tan ^{-1}\left (\sqrt [4]{-1} e^{\frac{1}{2} (e+f x)}\right )+f^2 x^2 \log \left (1-(-1)^{3/4} e^{\frac{1}{2} (e+f x)}\right )-f^2 x^2 \log \left ((-1)^{3/4} e^{\frac{1}{2} (e+f x)}+1\right )\right )}{f^3 \sqrt{a+i a \sinh (e+f x)}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.069, size = 0, normalized size = 0. \begin{align*} \int{{x}^{2}{\frac{1}{\sqrt{a+ia\sinh \left ( fx+e \right ) }}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\sqrt{i \, a \sinh \left (f x + e\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{2 i \, \sqrt{\frac{1}{2}} \sqrt{i \, a e^{\left (2 \, f x + 2 \, e\right )} + 2 \, a e^{\left (f x + e\right )} - i \, a} x^{2} e^{\left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )}}{a e^{\left (2 \, f x + 2 \, e\right )} - 2 i \, a e^{\left (f x + e\right )} - a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\sqrt{a \left (i \sinh{\left (e + f x \right )} + 1\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{2}}{\sqrt{i \, a \sinh \left (f x + e\right ) + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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